将1.721克CaSO4-xH2O加热,使其失去全部结晶水,这时剩余固体物质的质量是1.361克.计算1mol此结晶水合物中所含结晶水的物质的量.
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![将1.721克CaSO4-xH2O加热,使其失去全部结晶水,这时剩余固体物质的质量是1.361克.计算1mol此结晶水合物中所含结晶水的物质的量.](/uploads/image/z/4314762-18-2.jpg?t=%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B+%E5%B0%861.721%E5%85%8BCaSO4-xH2O%E5%8A%A0%E7%83%AD%2C%E4%BD%BF%E5%85%B6%E5%A4%B1%E5%8E%BB%E5%85%A8%E9%83%A8%E7%BB%93%E6%99%B6%E6%B0%B4%2C%E8%BF%99%E6%97%B6%E5%89%A9%E4%BD%99%E5%9B%BA%E4%BD%93%E7%89%A9%E8%B4%A8%E7%9A%84%E8%B4%A8%E9%87%8F%E6%98%AF1.361%E5%85%8B.%E8%AE%A1%E7%AE%971mol%E6%AD%A4%E7%BB%93%E6%99%B6%E6%B0%B4%E5%90%88%E7%89%A9%E4%B8%AD%E6%89%80%E5%90%AB%E7%BB%93%E6%99%B6%E6%B0%B4%E7%9A%84%E7%89%A9%E8%B4%A8%E7%9A%84%E9%87%8F.)
将1.721克CaSO4-xH2O加热,使其失去全部结晶水,这时剩余固体物质的质量是1.361克.计算1mol此结晶水合物中所含结晶水的物质的量.
将1.721克CaSO4-xH2O加热,使其失去全部结晶水,这时剩余固体物质的质量是1.361克.计算1mol此结晶水合物中所含结晶水的物质的量.
将1.721克CaSO4-xH2O加热,使其失去全部结晶水,这时剩余固体物质的质量是1.361克.计算1mol此结晶水合物中所含结晶水的物质的量.
CaSO4-xH2O ----> CaSO4 + xH2O,
136+18x 136 18x
1.721 1.361 1.721-1.361=0.360
根据题意,可有方程:
(136+18x):1.721=136:1.361,
136+18x=136*1.721/1.361=172,
x=(172-136)/18=2,
含水量=18x=36(克).
解2:
根据题意,可有方程:
(136+18x):1.721=18x:0.36,
(136+18x)*0.36=1.72*18x,
48.96+0.36*(18x)=1.72*(18x),
18x=48.96/1.36=36.
答:1mol此结晶水合物中所含结晶水的物质的量是36克.