a=2 b=1 求(a+1)(b+1)分之1+(a+2)(b+2)分之1+·······+(a+2008)(b+2008)分之1的值.
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 08:47:29
![a=2 b=1 求(a+1)(b+1)分之1+(a+2)(b+2)分之1+·······+(a+2008)(b+2008)分之1的值.](/uploads/image/z/3990937-49-7.jpg?t=a%3D2+b%3D1+%E6%B1%82%28a%2B1%29%28b%2B1%29%E5%88%86%E4%B9%8B1%2B%28a%2B2%29%28b%2B2%29%E5%88%86%E4%B9%8B1%2B%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%2B%EF%BC%88a%2B2008%29%28b%2B2008%29%E5%88%86%E4%B9%8B1%E7%9A%84%E5%80%BC.)
a=2 b=1 求(a+1)(b+1)分之1+(a+2)(b+2)分之1+·······+(a+2008)(b+2008)分之1的值.
a=2 b=1 求(a+1)(b+1)分之1+(a+2)(b+2)分之1+·······+(a+2008)(b+2008)分之1的值.
a=2 b=1 求(a+1)(b+1)分之1+(a+2)(b+2)分之1+·······+(a+2008)(b+2008)分之1的值.
利用公式1/[n(n+1)]=(1/n)-[1/(n+1)]