求好人帮忙解两个一元二次方程,x^2=2x+3 (x-2)(x+2)+1=0
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![求好人帮忙解两个一元二次方程,x^2=2x+3 (x-2)(x+2)+1=0](/uploads/image/z/3941268-60-8.jpg?t=%E6%B1%82%E5%A5%BD%E4%BA%BA%E5%B8%AE%E5%BF%99%E8%A7%A3%E4%B8%A4%E4%B8%AA%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%2Cx%5E2%3D2x%2B3+%28x-2%29%28x%2B2%29%2B1%3D0)
求好人帮忙解两个一元二次方程,x^2=2x+3 (x-2)(x+2)+1=0
求好人帮忙解两个一元二次方程,x^2=2x+3 (x-2)(x+2)+1=0
求好人帮忙解两个一元二次方程,x^2=2x+3 (x-2)(x+2)+1=0
1,
X^2-2X-3=0 (移向)
(X-3)(X+1)=0 (十字相乘)
解得:X=3 X=-1
2,
X^2-4+1=0 (乘开)
X^2=3
解得:X=根号3 X=-根号3