x(x+2y)-(x+2)^2+2x 其中x=2,y=-2分之1先化简,再求值。
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x(x+2y)-(x+2)^2+2x 其中x=2,y=-2分之1先化简,再求值。
x(x+2y)-(x+2)^2+2x 其中x=2,y=-2分之1
先化简,再求值。
x(x+2y)-(x+2)^2+2x 其中x=2,y=-2分之1先化简,再求值。
x(x+2y)-(x+2)^2+2x 其中x=2,y=-2分之1
解,得:
==2[2-2*(1/2)]-(2+2)^2+2*2
==2-16+4
==-10
带入啊,就可以算出来了,-10
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