已知(a²+b²)(a²+b²-8)+16=0,求a²+b²的值
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已知(a²+b²)(a²+b²-8)+16=0,求a²+b²的值
已知(a²+b²)(a²+b²-8)+16=0,求a²+b²的值
已知(a²+b²)(a²+b²-8)+16=0,求a²+b²的值
(a²+b²)(a²+b²-8)+16=0
(a²+b²)²-8(a²+b²)+16=0
(a²+b²-4)²=0
∴a²+b²=4
首平方尾平方,首尾二倍放中央,就可以做出来