已知A={(x,y)|x²+y²-2x-2y+2=0}求集合A
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已知A={(x,y)|x²+y²-2x-2y+2=0}求集合A
已知A={(x,y)|x²+y²-2x-2y+2=0}求集合A
已知A={(x,y)|x²+y²-2x-2y+2=0}求集合A
x²+y²-2x-2y+2=(x-1)²+(y-1)²=0
(x-1)²大于等于0 (y-1)²大于等于0
所以(x-1)²=0,即x=1 (y-1)²=0,即y=1
故A={(1,1)}
A={(1,1)}
A={(x,y)|x²+y²-2x-2y+2=0}
={(x,y)|(x-1)²+(y-1)²=0}
={(x,y)|x-1=0,y-1=0}
={(1,1)}