1若cos(π/6-x)=根号3/3,则cos(5π/6+x)2计算根号(1+2cos260度cos350度)/cos10度-根号(1-cos^2*170度)
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![1若cos(π/6-x)=根号3/3,则cos(5π/6+x)2计算根号(1+2cos260度cos350度)/cos10度-根号(1-cos^2*170度)](/uploads/image/z/3810979-19-9.jpg?t=1%E8%8B%A5cos%28%CF%80%2F6-x%29%3D%E6%A0%B9%E5%8F%B73%2F3%2C%E5%88%99cos%285%CF%80%2F6%2Bx%292%E8%AE%A1%E7%AE%97%E6%A0%B9%E5%8F%B7%EF%BC%881%2B2cos260%E5%BA%A6cos350%E5%BA%A6%EF%BC%89%2Fcos10%E5%BA%A6-%E6%A0%B9%E5%8F%B7%EF%BC%881-cos%5E2%2A170%E5%BA%A6%EF%BC%89)
1若cos(π/6-x)=根号3/3,则cos(5π/6+x)2计算根号(1+2cos260度cos350度)/cos10度-根号(1-cos^2*170度)
1若cos(π/6-x)=根号3/3,则cos(5π/6+x)2计算根号(1+2cos260度cos350度)/cos10度-根号(1-cos^2*170度)
1若cos(π/6-x)=根号3/3,则cos(5π/6+x)2计算根号(1+2cos260度cos350度)/cos10度-根号(1-cos^2*170度)
cos(5π/6+x)=cos[π-(π/6-x)]=-√3/3
√(1+2cos260度cos350度)/[cos10度-√(1-cos^2*170度)]
=√(1-2sin10度cos10度)/[cos10度-√(1-cos^2*170度)]
=(cos10度-sin10度)/(cos10度-sin170度)
=(cos10度-sin10度)/(cos10度-sin10度)
=1