1)诺sin(π/6-x)=1/3,则cos(2π/3+2x)等于2)诺tanx=2,则tan2(x-π/4)等于
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![1)诺sin(π/6-x)=1/3,则cos(2π/3+2x)等于2)诺tanx=2,则tan2(x-π/4)等于](/uploads/image/z/3787533-45-3.jpg?t=1%29%E8%AF%BAsin%EF%BC%88%CF%80%2F6-x%EF%BC%89%3D1%2F3%2C%E5%88%99cos%EF%BC%882%CF%80%2F3%2B2x%EF%BC%89%E7%AD%89%E4%BA%8E2%29%E8%AF%BAtanx%3D2%2C%E5%88%99tan2%EF%BC%88x-%CF%80%2F4%EF%BC%89%E7%AD%89%E4%BA%8E)
1)诺sin(π/6-x)=1/3,则cos(2π/3+2x)等于2)诺tanx=2,则tan2(x-π/4)等于
1)诺sin(π/6-x)=1/3,则cos(2π/3+2x)等于
2)诺tanx=2,则tan2(x-π/4)等于
1)诺sin(π/6-x)=1/3,则cos(2π/3+2x)等于2)诺tanx=2,则tan2(x-π/4)等于
不知道对不对哈
1)sin(π/2-(π/6-x))=cos(π/3+x)=+ -2根号2/3
cos(2π/3+2x)=cos2(π/3+x)=7/9
2)tan(x-π/4)=(tanx-tanπ/4)/1+tanx*tanπ/4=1/3
tan2(x-π/4)=2tan(x-π/4)/1-tan(x-π/4)的平方=3/4