若abc=1,求a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 11:58:18
![若abc=1,求a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)](/uploads/image/z/3653527-31-7.jpg?t=%E8%8B%A5abc%3D1%2C%E6%B1%82a%2F%28ab%2Ba%2B1%29%2Bb%2F%28bc%2Bb%2B1%29%2Bc%2F%28ac%2Bc%2B1%29)
若abc=1,求a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)
若abc=1,求a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)
若abc=1,求a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)
原式=a/(ab+a+1)+ab/(abc+ab+a)+abc/(ac.ab+abc+ab)
=a/(ab+a+1)+ab/(1+ab+a)+1/(a+1+ab)
=(a+ab+1)/(ab+a+1)
=1
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