函数f(x)=(sin x-1)/(3-2cos x-2sin x)^(1/2) (0≤x≤2π) 的值域是( )A.[-1/2^(1/2) ,0] B.[-1,0] C.[ -2^(1/2) ,0] D.[ -3^(1/2) ,0]已知答案是:B.请问如何得到?
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![函数f(x)=(sin x-1)/(3-2cos x-2sin x)^(1/2) (0≤x≤2π) 的值域是( )A.[-1/2^(1/2) ,0] B.[-1,0] C.[ -2^(1/2) ,0] D.[ -3^(1/2) ,0]已知答案是:B.请问如何得到?](/uploads/image/z/3647699-35-9.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%3D%28sin+x-1%29%2F%283-2cos+x-2sin+x%29%5E%281%2F2%29+%280%E2%89%A4x%E2%89%A42%CF%80%29+%E7%9A%84%E5%80%BC%E5%9F%9F%E6%98%AF%28+%29A.%5B-1%2F2%5E%281%2F2%29+%2C0%5D+B.%5B-1%2C0%5D+C.%5B+-2%5E%281%2F2%29+%2C0%5D+D.%5B+-3%5E%281%2F2%29+%2C0%5D%E5%B7%B2%E7%9F%A5%E7%AD%94%E6%A1%88%E6%98%AF%EF%BC%9AB.%E8%AF%B7%E9%97%AE%E5%A6%82%E4%BD%95%E5%BE%97%E5%88%B0%3F)
函数f(x)=(sin x-1)/(3-2cos x-2sin x)^(1/2) (0≤x≤2π) 的值域是( )A.[-1/2^(1/2) ,0] B.[-1,0] C.[ -2^(1/2) ,0] D.[ -3^(1/2) ,0]已知答案是:B.请问如何得到?
函数f(x)=(sin x-1)/(3-2cos x-2sin x)^(1/2) (0≤x≤2π) 的值域是( )
A.[-1/2^(1/2) ,0] B.[-1,0] C.[ -2^(1/2) ,0] D.[ -3^(1/2) ,0]
已知答案是:B.请问如何得到?
函数f(x)=(sin x-1)/(3-2cos x-2sin x)^(1/2) (0≤x≤2π) 的值域是( )A.[-1/2^(1/2) ,0] B.[-1,0] C.[ -2^(1/2) ,0] D.[ -3^(1/2) ,0]已知答案是:B.请问如何得到?
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