如图,在▱ABCD中,AE⊥BC,AF⊥CD,E,F为垂足,已知角B=60°,AE:AF=3:4 ▱ABCD的周长为56((1)求证:BE+DF=CE+CF(2)求AB,AD长(3)求S▱ABCD
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![如图,在▱ABCD中,AE⊥BC,AF⊥CD,E,F为垂足,已知角B=60°,AE:AF=3:4 ▱ABCD的周长为56((1)求证:BE+DF=CE+CF(2)求AB,AD长(3)求S▱ABCD](/uploads/image/z/3529610-26-0.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%26%239649%3BABCD%E4%B8%AD%2CAE%E2%8A%A5BC%2CAF%E2%8A%A5CD%2CE%2CF%E4%B8%BA%E5%9E%82%E8%B6%B3%2C%E5%B7%B2%E7%9F%A5%E8%A7%92B%3D60%C2%B0%2CAE%EF%BC%9AAF%3D3%EF%BC%9A4+%26%239649%3BABCD%E7%9A%84%E5%91%A8%E9%95%BF%E4%B8%BA56%EF%BC%88%281%29%E6%B1%82%E8%AF%81%EF%BC%9ABE%2BDF%3DCE%2BCF%282%29%E6%B1%82AB%2CAD%E9%95%BF%283%29%E6%B1%82S%26%239649%3BABCD)
如图,在▱ABCD中,AE⊥BC,AF⊥CD,E,F为垂足,已知角B=60°,AE:AF=3:4 ▱ABCD的周长为56((1)求证:BE+DF=CE+CF(2)求AB,AD长(3)求S▱ABCD
如图,在▱ABCD中,AE⊥BC,AF⊥CD,E,F为垂足,已知角B=60°,AE:AF=3:4 ▱ABCD的周长为56(
(1)求证:BE+DF=CE+CF
(2)求AB,AD长
(3)求S▱ABCD
如图,在▱ABCD中,AE⊥BC,AF⊥CD,E,F为垂足,已知角B=60°,AE:AF=3:4 ▱ABCD的周长为56((1)求证:BE+DF=CE+CF(2)求AB,AD长(3)求S▱ABCD
(1)BE+DF=1/2(BC+CD)=CE+CF
(2)AD=4/3AB,2*(AB+4/3AB)=56,AB=12,AD=16
(3)S▱ABCD=√3/2*(AB*AD)=96√3
题目能说完整吗