a=2008,b=2007.c=2006,则多项式a^2+b^2+c^2-ab-ac-bcthanks!
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![a=2008,b=2007.c=2006,则多项式a^2+b^2+c^2-ab-ac-bcthanks!](/uploads/image/z/346775-23-5.jpg?t=a%3D2008%2Cb%3D2007.c%3D2006%2C%E5%88%99%E5%A4%9A%E9%A1%B9%E5%BC%8Fa%5E2%2Bb%5E2%2Bc%5E2-ab-ac-bcthanks%21)
a=2008,b=2007.c=2006,则多项式a^2+b^2+c^2-ab-ac-bcthanks!
a=2008,b=2007.c=2006,则多项式a^2+b^2+c^2-ab-ac-bc
thanks!
a=2008,b=2007.c=2006,则多项式a^2+b^2+c^2-ab-ac-bcthanks!
a^2+b^2+c^2-ab-ac-bc
=1/2[(a-b)^2+(b-c)^2+(a-c)^2]
=1/2(1+1+4)
=3
a=c+2 b=c+1
所以多项式=(c+2)²+(c+1)²+c²-(c+2)(c+1)-(c+2)c-(c+1)c=3(含c的项都消掉了)