用因式法解方程(1-根号下2)x²=(1+根号下2)x
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![用因式法解方程(1-根号下2)x²=(1+根号下2)x](/uploads/image/z/3027650-50-0.jpg?t=%E7%94%A8%E5%9B%A0%E5%BC%8F%E6%B3%95%E8%A7%A3%E6%96%B9%E7%A8%8B%281-%E6%A0%B9%E5%8F%B7%E4%B8%8B2%EF%BC%89x%26%23178%3B%3D%EF%BC%881%2B%E6%A0%B9%E5%8F%B7%E4%B8%8B2%EF%BC%89x)
用因式法解方程(1-根号下2)x²=(1+根号下2)x
用因式法解方程(1-根号下2)x²=(1+根号下2)x
用因式法解方程(1-根号下2)x²=(1+根号下2)x
解由(1-√2)x^2=(1+√2)x
移项得(1-√2)x^2-(1+√2)x=0
即x[(1-√2)x-(1+√2)]=0
即x=0或(1-√2)x-(1+√2)=0
即x=0或(1-√2)x=(1+√2)
解得x=0或x=(1+√2)/(1-√2)
即为x=0或x=-3-2√2.
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