2.已知9am+¹bn+¹与-2a²m-¹b²n-1 的积与5a³b6是同类项,求m、n
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![2.已知9am+¹bn+¹与-2a²m-¹b²n-1 的积与5a³b6是同类项,求m、n](/uploads/image/z/3020212-28-2.jpg?t=2.%E5%B7%B2%E7%9F%A59am%2B%26%23185%3Bbn%2B%26%23185%3B%E4%B8%8E-2a%26%23178%3Bm-%26%23185%3Bb%26%23178%3Bn-1+%E7%9A%84%E7%A7%AF%E4%B8%8E5a%26%23179%3Bb6%E6%98%AF%E5%90%8C%E7%B1%BB%E9%A1%B9%2C%E6%B1%82m%E3%80%81n)
2.已知9am+¹bn+¹与-2a²m-¹b²n-1 的积与5a³b6是同类项,求m、n
2.已知9am+¹bn+¹与-2a²m-¹b²n-1 的积与5a³b6是同类项,求m、n
2.已知9am+¹bn+¹与-2a²m-¹b²n-1 的积与5a³b6是同类项,求m、n
9am+nbn+1•(-2a2m-1b2n-1)
=9×(-2)•am+1•a2m-1•bn+1•b2n-1
=-18a3mb3n
因为与5a3b6是同类项,
所以3m=3,3n=6,
解得m=1,n=2.