设f(x)=-1/2x²+x+1,求f(-1),f(1),f(3),f(6)
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![设f(x)=-1/2x²+x+1,求f(-1),f(1),f(3),f(6)](/uploads/image/z/3001252-4-2.jpg?t=%E8%AE%BEf%28x%29%3D-1%2F2x%26%23178%3B%2Bx%2B1%2C%E6%B1%82f%28-1%29%2Cf%281%29%2Cf%283%29%2Cf%286%29)
设f(x)=-1/2x²+x+1,求f(-1),f(1),f(3),f(6)
设f(x)=-1/2x²+x+1,求f(-1),f(1),f(3),f(6)
设f(x)=-1/2x²+x+1,求f(-1),f(1),f(3),f(6)
解:
f(-1)=-1/2-1+1=-1/2
f(1)=-1/2+1+1=2-1/2=3/2
f(3)=-9/2+3+1=4-9/2=-1/2
f(6)=-18+6+1=-11