求证:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²证明:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²是有理数,:(√是根号)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/28 10:27:49
![求证:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²证明:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²是有理数,:(√是根号)](/uploads/image/z/3000738-66-8.jpg?t=%E6%B1%82%E8%AF%81%3A%E2%88%9Aa%26%23178%3Bb%26%23178%3B%2F%EF%BC%88a-b%EF%BC%89%26%23178%3B%EF%BC%8Bb%26%23178%3Bc%26%23178%3B%2F%EF%BC%88b-c%EF%BC%89%26%23178%3B%EF%BC%8Bc%26%23178%3Ba%26%23178%3B%2F%EF%BC%88c-a%EF%BC%89%26%23178%3B%E8%AF%81%E6%98%8E%3A%E2%88%9Aa%26%23178%3Bb%26%23178%3B%2F%EF%BC%88a-b%EF%BC%89%26%23178%3B%EF%BC%8Bb%26%23178%3Bc%26%23178%3B%2F%EF%BC%88b-c%EF%BC%89%26%23178%3B%EF%BC%8Bc%26%23178%3Ba%26%23178%3B%2F%EF%BC%88c-a%EF%BC%89%26%23178%3B%E6%98%AF%E6%9C%89%E7%90%86%E6%95%B0%EF%BC%8C%3A%EF%BC%88%E2%88%9A%E6%98%AF%E6%A0%B9%E5%8F%B7%EF%BC%89)
求证:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²证明:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²是有理数,:(√是根号)
求证:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²
证明:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²是有理数,:(√是根号)
求证:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²证明:√a²b²/(a-b)²+b²c²/(b-c)²+c²a²/(c-a)²是有理数,:(√是根号)
只有等式左边,要证明什么?另外,是不是少了根号?
根号到哪里?第一项的分子有根号?其他项没有是吗?