已知abc在数轴上如图,化简√a²-|a+b|+√(c-a)²+|b+c|——————————————————————→b a 0 c
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 02:40:35
![已知abc在数轴上如图,化简√a²-|a+b|+√(c-a)²+|b+c|——————————————————————→b a 0 c](/uploads/image/z/2811427-43-7.jpg?t=%E5%B7%B2%E7%9F%A5abc%E5%9C%A8%E6%95%B0%E8%BD%B4%E4%B8%8A%E5%A6%82%E5%9B%BE%2C%E5%8C%96%E7%AE%80%E2%88%9Aa%26%23178%3B-%7Ca%2Bb%7C%2B%E2%88%9A%EF%BC%88c-a%EF%BC%89%26%23178%3B%2B%7Cb%2Bc%7C%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%86%92b+a+0+c)
已知abc在数轴上如图,化简√a²-|a+b|+√(c-a)²+|b+c|——————————————————————→b a 0 c
已知abc在数轴上如图,化简√a²-|a+b|+√(c-a)²+|b+c|
——————————————————————→
b a 0 c
已知abc在数轴上如图,化简√a²-|a+b|+√(c-a)²+|b+c|——————————————————————→b a 0 c
原式=√a2-|a+b|+√(c-a)2+|b+c|
=|a|-[-﹙a+b﹚]+|c-a|+[﹣﹙b+c﹚]
=-a+a+b+c-a-b-c
=-a