#include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i
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![#include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i](/uploads/image/z/2722009-49-9.jpg?t=%23include++void+fun%28int+a%2C+int+b%29+%7B+int+t%3B+t%3Da%3B+a%3Db%3B+b%3Dt%3Bmain%28%29+%7B++int++c%5B10%5D%3D%7B1%2C2%2C3%2C4%2C5%2C6%2C7%2C8%2C9%2C0%29%2C+i%3B++++for+%28i%3D0%3B+i)
#include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i
#include void fun(int a, int b) { int t; t=a; a=b; b=t;
main()
{ int c[10]={1,2,3,4,5,6,7,8,9,0), i;
for (i=0; i
#include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i
答案就是A
void fun(int a,int b) { int t; t=a; a=b; b=t;}你改成void fun(int &a,int &b) { int t; t=a; a=b; b=t;)就明白了,需要用到引用参数值在函数结束后才会改变,否则不变