已知x,y满足x^2+4y^2+2x-4y+2=0,则根号5x^2+16y^2=?
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![已知x,y满足x^2+4y^2+2x-4y+2=0,则根号5x^2+16y^2=?](/uploads/image/z/2683609-25-9.jpg?t=%E5%B7%B2%E7%9F%A5x%2Cy%E6%BB%A1%E8%B6%B3x%EF%BC%BE2%2B4y%EF%BC%BE2%2B2x-4y%2B2%3D0%2C%E5%88%99%E6%A0%B9%E5%8F%B75x%EF%BC%BE2%2B16y%EF%BC%BE2%3D%3F)
已知x,y满足x^2+4y^2+2x-4y+2=0,则根号5x^2+16y^2=?
已知x,y满足x^2+4y^2+2x-4y+2=0,则根号5x^2+16y^2=?
已知x,y满足x^2+4y^2+2x-4y+2=0,则根号5x^2+16y^2=?
x^2+4y^2+2x-4y+2=0
(x+1)^2+(2y-1)^2=0
x+1=0,2y-1=0
x=-1,y=1/2
√5x^2+16y^2=√(5*(-1))^2+16*(1/2)^2
=5+16*1/4
=5+4=9
是否可以解决您的问题?
x^2+4y^2+2x-4y+2=0
x^2+2x+1+4y^2-4y+1=0
(x+1)^2+(2y+1)^2=0
x=-1 y=-1/2
5x^2+16y^2=5*(-1)^2+16*(-1/2)^2=5+4=9