先化简再求值(a+1)²-(a+1)(a+3),其中a=-2
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先化简再求值(a+1)²-(a+1)(a+3),其中a=-2
先化简再求值(a+1)²-(a+1)(a+3),其中a=-2
先化简再求值(a+1)²-(a+1)(a+3),其中a=-2
(a+1)²-(a+1)(a+3)
=a²+2a+1-a²-4a-3
=-2a-2
=-2x(-2)-2
=4-2
=2
(a+1)²-(a+1)(a+3),
=a²+2a+1-(a²+a+3a+3)
=a²+2a+1-a²-4a-3
=-2a-2
原式==-2x(-2)-2=2