求函数y=log2 x/2*log2x/4,x∈[2√2,8]的值域
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![求函数y=log2 x/2*log2x/4,x∈[2√2,8]的值域](/uploads/image/z/2670012-36-2.jpg?t=%E6%B1%82%E5%87%BD%E6%95%B0y%3Dlog2+x%2F2%2Alog2x%2F4%2Cx%E2%88%88%5B2%E2%88%9A2%2C8%5D%E7%9A%84%E5%80%BC%E5%9F%9F)
求函数y=log2 x/2*log2x/4,x∈[2√2,8]的值域
求函数y=log2 x/2*log2x/4,x∈[2√2,8]的值域
求函数y=log2 x/2*log2x/4,x∈[2√2,8]的值域
y=(log2 x)/(log2 1/2)*(log2 x)/(log2 1/4)
=(log2 x)^2/2
令t=log2 x,3/2