如果实数x,y满足(x²+y²+1)(x²+y²-3)=-4,则x²+y²的值?
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![如果实数x,y满足(x²+y²+1)(x²+y²-3)=-4,则x²+y²的值?](/uploads/image/z/2669406-6-6.jpg?t=%E5%A6%82%E6%9E%9C%E5%AE%9E%E6%95%B0x%2Cy%E6%BB%A1%E8%B6%B3%28x%26%23178%3B%2By%26%23178%3B%2B1%29%28x%26%23178%3B%2By%26%23178%3B-3%29%3D-4%2C%E5%88%99x%26%23178%3B%2By%26%23178%3B%E7%9A%84%E5%80%BC%3F)
如果实数x,y满足(x²+y²+1)(x²+y²-3)=-4,则x²+y²的值?
如果实数x,y满足(x²+y²+1)(x²+y²-3)=-4,则x²+y²的值?
如果实数x,y满足(x²+y²+1)(x²+y²-3)=-4,则x²+y²的值?
你可以设
x²+y²=t,就容易算出来了
(x²+y²+1)(x²+y²-3)=-4
(x²+y²)²-2(x²+y²)-3=-4
(x²+y²)²-2(x²+y²)+1=0
(x²+y²-1)²=0
x²+y²-1=0
x²+y²=1