已知1/2|2x-1|+1/4(y-4)²=0,求多项式1-xy+xy²的值
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![已知1/2|2x-1|+1/4(y-4)²=0,求多项式1-xy+xy²的值](/uploads/image/z/2668894-70-4.jpg?t=%E5%B7%B2%E7%9F%A51%2F2%7C2x-1%7C%2B1%2F4%28y-4%29%26%23178%3B%3D0%2C%E6%B1%82%E5%A4%9A%E9%A1%B9%E5%BC%8F1-xy%2Bxy%26%23178%3B%E7%9A%84%E5%80%BC)
已知1/2|2x-1|+1/4(y-4)²=0,求多项式1-xy+xy²的值
已知1/2|2x-1|+1/4(y-4)²=0,求多项式1-xy+xy²的值
已知1/2|2x-1|+1/4(y-4)²=0,求多项式1-xy+xy²的值
题意得
2x-1=0 y-4=0
∴x=1/2 y=4
∴1-xy+xy²
=1-1/2×4+1/2×4²
=1-2+8
=7