如果x/2=y/3=z/4,求(2x-y+3z)/(x+y-z)的值
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![如果x/2=y/3=z/4,求(2x-y+3z)/(x+y-z)的值](/uploads/image/z/263845-37-5.jpg?t=%E5%A6%82%E6%9E%9Cx%2F2%3Dy%2F3%3Dz%2F4%2C%E6%B1%82%282x-y%2B3z%29%2F%28x%2By-z%29%E7%9A%84%E5%80%BC)
如果x/2=y/3=z/4,求(2x-y+3z)/(x+y-z)的值
如果x/2=y/3=z/4,求(2x-y+3z)/(x+y-z)的值
如果x/2=y/3=z/4,求(2x-y+3z)/(x+y-z)的值
令x/2=y/3=z/4=a, 那么, x=2a; y=3a; z=4a, 代到(2x-y+3z)/(x+y-z)里面,就等于(4a-3a+12a)/(2a+3a-4a);
就等于13a/a = 13