已知|a+1/2|+(b-3)²=0 求代数式[(2a+b)²+(2a+b)(b-2a)-6b]÷2b的值!
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![已知|a+1/2|+(b-3)²=0 求代数式[(2a+b)²+(2a+b)(b-2a)-6b]÷2b的值!](/uploads/image/z/2590759-55-9.jpg?t=%E5%B7%B2%E7%9F%A5%EF%BD%9Ca%2B1%2F2%EF%BD%9C%2B%EF%BC%88b-3%EF%BC%89%26%23178%3B%3D0+%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%5B%EF%BC%882a%2Bb%EF%BC%89%26%23178%3B%2B%EF%BC%882a%2Bb%EF%BC%89%EF%BC%88b-2a%EF%BC%89-6b%5D%C3%B72b%E7%9A%84%E5%80%BC%21)
已知|a+1/2|+(b-3)²=0 求代数式[(2a+b)²+(2a+b)(b-2a)-6b]÷2b的值!
已知|a+1/2|+(b-3)²=0 求代数式[(2a+b)²+(2a+b)(b-2a)-6b]÷2b的值!
已知|a+1/2|+(b-3)²=0 求代数式[(2a+b)²+(2a+b)(b-2a)-6b]÷2b的值!
答:
|a+1/2|+(b-3)²=0
绝对值和平方数为非负数,则有:a+1/2=0
b-3=0
解得:a=-1/2,b=3
[(2a+b)²+(2a+b)(b-2a)-6b]÷2b
=(4a²+4ab+b²-4a²+b²)÷(2b)
=(2b²+4ab)÷(2b)
=b+2a
=3-1
=2