已知x+y=2,xy=0,求x²+y²与(x-y)²
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已知x+y=2,xy=0,求x²+y²与(x-y)²
已知x+y=2,xy=0,求x²+y²与(x-y)²
已知x+y=2,xy=0,求x²+y²与(x-y)²
x²+y²
=(x+y)²-2xy
=2²-0
=4
(x-y)²
=(x+y)²-4xy
=2²-0
=4
若X=0,Y=2 x²+y²=4 (x-y)²=4
若x=2,y=0 x²+y²=4 (x-y)²=4
不就这样。。。。
因为x+y=2 ,xy=0 所以x=0 y=2 或 x=2 y=0 所以x²+y²=4 (x-y)²=4