计算20042003²+1/20042002²+20042004²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 05:44:42
![计算20042003²+1/20042002²+20042004²](/uploads/image/z/2492970-42-0.jpg?t=%E8%AE%A1%E7%AE%9720042003%26%23178%3B%2B1%2F20042002%26%23178%3B%2B20042004%26%23178%3B)
计算20042003²+1/20042002²+20042004²
计算20042003²+1/20042002²+20042004²
计算20042003²+1/20042002²+20042004²
(20042003²+1)/(20042002²+20042004²)
=(20042003²+1)/[(20042003-1)²+(20042003+1)²)]
=(20042003²+1)/(20042003²-2×20042003+1+20042003²+2×20042003+1)
=(20042003²+1)/(2×20042003²+2)
=1/2