已知实数x、y、z满足(x²-6xy+10y²+4y)y²+4y+|(z-3/2)²-1/4|+4=0求(x+y)²的值
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![已知实数x、y、z满足(x²-6xy+10y²+4y)y²+4y+|(z-3/2)²-1/4|+4=0求(x+y)²的值](/uploads/image/z/2491303-31-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9E%E6%95%B0x%E3%80%81y%E3%80%81z%E6%BB%A1%E8%B6%B3%28x%26%23178%3B-6xy%2B10y%26%23178%3B%2B4y%29y%26%23178%3B%2B4y%2B%7C%EF%BC%88z-3%EF%BC%8F2%EF%BC%89%26%23178%3B-1%EF%BC%8F4%7C%2B4%3D0%E6%B1%82%EF%BC%88x%2By%EF%BC%89%26%23178%3B%E7%9A%84%E5%80%BC)
已知实数x、y、z满足(x²-6xy+10y²+4y)y²+4y+|(z-3/2)²-1/4|+4=0求(x+y)²的值
已知实数x、y、z满足(x²-6xy+10y²+4y)y²+4y+|(z-3/2)²-1/4|+4=0
求(x+y)²的值
已知实数x、y、z满足(x²-6xy+10y²+4y)y²+4y+|(z-3/2)²-1/4|+4=0求(x+y)²的值
x²-6xy+10y²+4y+|(z-3/2)²-1/4|+4=0 删除了一点我认为没有的内容
x²-6xy+9y²+y²+4y+4+|(z-3/2)²-1/4|=0
(x-3y)²+(y+2)²+|(z-3/2)²-1/4|=0
∴x-3y=0
y+2=0
∴x=-6
y=-2
(x+y)²=(-6-2)²=64