x+y=960 (1+30%)x+(1+25%)y=1228 二元一次方程,
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![x+y=960 (1+30%)x+(1+25%)y=1228 二元一次方程,](/uploads/image/z/243498-66-8.jpg?t=x%2By%3D960+%281%2B30%25%29x%2B%281%2B25%25%29y%3D1228+%E4%BA%8C%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B%2C)
x+y=960 (1+30%)x+(1+25%)y=1228 二元一次方程,
x+y=960 (1+30%)x+(1+25%)y=1228 二元一次方程,
x+y=960 (1+30%)x+(1+25%)y=1228 二元一次方程,
因为 x+y=960
所以 y=960-x
又因为 1.3x+1.25y=1228
所以代入 1.3x+1.25×(960-x)=1228
.1.3x-1.25x +1.25×960 =1228
0.05x=28
x=560
y=960-560=400
{6/x+y+10/x-y=30 6/x+y-10/x-y=-1
x>=1,x-y
y=x-1(x
求导 y=[x/(1+x)]^x
y'-(1/x)y=xe^-x
y-x=30 y+1=3(x+1)
z=0.015x*x+y*x*0.05+(1-x-y)*2.5*(x+y) x>0.35.xy>0.70x+y
1=x+y 2=20x+30y
已知x+y=a,2x-y=-2a,求[(x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值
x.y都是自然数,且x(x-u)-y(y-x)+12,求x.y得值快1且x(x-y)-y(y-x)=12
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
y'/y=1/x
解方程组:x+y=xy=11 (1) x*x*y+x*y*y=30 (2)
y(x+y)+(x-y)²-(x+y)(x-y),其中x=-1/3,y=3
(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
请问60%x+20%y=30%(x+y) 怎么得到x:y=1:3
x+y=540 (x+30)÷y=2/1 x=?y=?