已知(x+3)+丨X-y+10丨=0 ,求5x²y-[2x²y-(3xy-xy²)-3x²]-2xy²-y²的值
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![已知(x+3)+丨X-y+10丨=0 ,求5x²y-[2x²y-(3xy-xy²)-3x²]-2xy²-y²的值](/uploads/image/z/224638-70-8.jpg?t=%E5%B7%B2%E7%9F%A5%28x%2B3%EF%BC%89%2B%E4%B8%A8X-y%2B10%E4%B8%A8%3D0+%2C%E6%B1%825x%26%23178%3By-%5B2x%26%23178%3By-%EF%BC%883xy-xy%26%23178%3B%EF%BC%89-3x%26%23178%3B%5D-2xy%26%23178%3B-y%26%23178%3B%E7%9A%84%E5%80%BC)
已知(x+3)+丨X-y+10丨=0 ,求5x²y-[2x²y-(3xy-xy²)-3x²]-2xy²-y²的值
已知(x+3)+丨X-y+10丨=0 ,求5x²y-[2x²y-(3xy-xy²)-3x²]-2xy²-y²的值
已知(x+3)+丨X-y+10丨=0 ,求5x²y-[2x²y-(3xy-xy²)-3x²]-2xy²-y²的值
严重怀疑你掉了(x+3)的平方那个2