当x=-1 y=1/2 求多项式2(x-2y)²-4(2x-y)+(x-2y)²-3(2x-y)的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/01 23:31:14
![当x=-1 y=1/2 求多项式2(x-2y)²-4(2x-y)+(x-2y)²-3(2x-y)的值](/uploads/image/z/2114150-14-0.jpg?t=%E5%BD%93x%3D-1+y%3D1%2F2+%E6%B1%82%E5%A4%9A%E9%A1%B9%E5%BC%8F2%28x-2y%29%26%23178%3B-4%282x-y%29%2B%28x-2y%29%26%23178%3B-3%282x-y%29%E7%9A%84%E5%80%BC)
当x=-1 y=1/2 求多项式2(x-2y)²-4(2x-y)+(x-2y)²-3(2x-y)的值
当x=-1 y=1/2 求多项式2(x-2y)²-4(2x-y)+(x-2y)²-3(2x-y)的值
当x=-1 y=1/2 求多项式2(x-2y)²-4(2x-y)+(x-2y)²-3(2x-y)的值
把x.y都带进去,2(-1-1)^2-4(-2-1/2)+(-1-1)^2-3(-2-1/2)
=2*4+10+4+15/2
= 29.5
29.5
先化简多项式,3(x-2y)^2-7(2x-y)然后代入数值得29.5