(x+1)(x+1)-(x-1)(1-x)=6 求x的解 (x-2)(2x+1)=(2x+1)(x+1) 用因式分解解方程
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![(x+1)(x+1)-(x-1)(1-x)=6 求x的解 (x-2)(2x+1)=(2x+1)(x+1) 用因式分解解方程](/uploads/image/z/1987597-37-7.jpg?t=%28x%2B1%29%28x%2B1%29-%28x-1%29%281-x%29%3D6+%E6%B1%82x%E7%9A%84%E8%A7%A3+%EF%BC%88x-2%29%EF%BC%882x%2B1%EF%BC%89%3D%282x%2B1%29%28x%2B1%29+%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E8%A7%A3%E6%96%B9%E7%A8%8B)
(x+1)(x+1)-(x-1)(1-x)=6 求x的解 (x-2)(2x+1)=(2x+1)(x+1) 用因式分解解方程
(x+1)(x+1)-(x-1)(1-x)=6 求x的解 (x-2)(2x+1)=(2x+1)(x+1) 用因式分解解方程
(x+1)(x+1)-(x-1)(1-x)=6 求x的解 (x-2)(2x+1)=(2x+1)(x+1) 用因式分解解方程
(x+1)(x+1)-(x-1)(1-x)=6
(x+1)^2 +(x-1)^2 = 6
2x^2+2 = 6
x^2=2
x1=-√2,x2=√2
(x-2)(2x+1)=(2x+1)(x+1)
(x-2)(2x+1)-(2x+1)(x+1) = 0
(2x+1)(x-2-x-1) = 0
(2x+1)(-3) = 0
2x+1=0
x=-1/2
(x+1)(x+1)-(x-1)(1-x)=6
x^2+2x+1+x^2-2x+1-6=0
2x^2-4=0
x^2=2
x=±√2
(x-2)(2x+1)=(2x+1)(x+1)
(x-2)(2x+1)-(2x+1)(x+1)=0
(2x+1)(x-2-x-1)=0
-3(2x+1)=0
x=-1/2
x/x+(1-x)/x-1/x
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(x+1)(x-1)(x-x+1)(x+x+1)
分解因式----(X*X-X)(X*X-X-2)+1
X(X-1)=X
1.1/x|x/(x+1)|
x/x-1[1+(x-1/x)]
x-1/x÷(x-1/x)
】x(x+1)+x^2(x-1)
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
x>1/1-x
x+1/x-1
(X + 1) /(x - 1)
(1+X)/(1-X)
|x+1|+|x-1|
/X-3/-/X-1/