[(4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3)]
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 22:33:17
![[(4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3)]](/uploads/image/z/1835270-62-0.jpg?t=%5B%EF%BC%884a%26%23178%3B-4a%29%2F%28a%26%23178%3B2a%2B1%29%5D%C3%B7%5Ba%2B1%2F%28a-1%29-%28a-1%29%2F%28a%2B1%29%5D%C3%97%5B1%2F%283a%2B3%EF%BC%89%5D)
[(4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3)]
[(4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3)]
[(4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3)]
原式=(4a(a-1)/2aaa+1)x((a+1)(a-1)/4a)x(1/3(a+1))
=(aa+1+2a)/(6aaa+3)