已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2]...求sin(a+B)已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2],f(3a+兀/2)=10/13,f(3B+兀/2)=6/5求sin(a+B)的值
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![已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2]...求sin(a+B)已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2],f(3a+兀/2)=10/13,f(3B+兀/2)=6/5求sin(a+B)的值](/uploads/image/z/1729862-62-2.jpg?t=%E5%B7%B2%E7%9F%A5f%28x%29%3D2sin%281%2F3x-%E5%85%80%2F6%29%2Cx%E5%B1%9E%E4%BA%8ER%2C%281%29%E6%B1%82f%280%29%E7%9A%84%E5%80%BC%282%29%E8%AE%BEa%2CB%E5%B1%9E%5B0%2C%E5%85%80%2F2%5D...%E6%B1%82sin%28a%2BB%29%E5%B7%B2%E7%9F%A5f%28x%29%3D2sin%281%2F3x-%E5%85%80%2F6%29%2Cx%E5%B1%9E%E4%BA%8ER%2C%281%29%E6%B1%82f%280%29%E7%9A%84%E5%80%BC%282%29%E8%AE%BEa%2CB%E5%B1%9E%5B0%2C%E5%85%80%2F2%5D%2Cf%283a%2B%E5%85%80%2F2%29%3D10%2F13%2Cf%283B%2B%E5%85%80%2F2%29%3D6%2F5%E6%B1%82sin%28a%2BB%29%E7%9A%84%E5%80%BC)
已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2]...求sin(a+B)已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2],f(3a+兀/2)=10/13,f(3B+兀/2)=6/5求sin(a+B)的值
已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2]...求sin(a+B)
已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2],f(3a+兀/2)=10/13,f(3B+兀/2)=6/5求sin(a+B)的值
已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2]...求sin(a+B)已知f(x)=2sin(1/3x-兀/6),x属于R,(1)求f(0)的值(2)设a,B属[0,兀/2],f(3a+兀/2)=10/13,f(3B+兀/2)=6/5求sin(a+B)的值
1、
f(x)=2sin(1/3x-π/6),
f(0)=2sin(-π/6)=-2*(1/2)=-1.
2、
f(3a+π/2)=2sin(a+π/6-π/6)=2sina=10/13,所以:sina=5/13;
f(3b+π/2)=2sin(b+π/6-π/6)=2sinb=6/5,所以:sinb=3/5;
又因为a,b在第一象限,所以:cosa=12/13,cosb=4/5.
所以:
sin(a+b)
=sinacosb+cosasinb
=(5/13)(4/5)+(12/13)(3/5)
=56/65.