已知f(α)=(sin(Π/2-α)cos(2Π-α)tan(-α+3Π))/(tan(Π+α)sin(Π/2+α)),化简f(α)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 16:24:37
![已知f(α)=(sin(Π/2-α)cos(2Π-α)tan(-α+3Π))/(tan(Π+α)sin(Π/2+α)),化简f(α)](/uploads/image/z/1729769-41-9.jpg?t=%E5%B7%B2%E7%9F%A5f%28%CE%B1%29%3D%28sin%28%CE%A0%EF%BC%8F2-%CE%B1%29cos%282%CE%A0-%CE%B1%29tan%28-%CE%B1%2B3%CE%A0%29%29%EF%BC%8F%28tan%28%CE%A0%2B%CE%B1%29sin%28%CE%A0%EF%BC%8F2%EF%BC%8B%CE%B1%29%29%2C%E5%8C%96%E7%AE%80f%28%CE%B1%29)
已知f(α)=(sin(Π/2-α)cos(2Π-α)tan(-α+3Π))/(tan(Π+α)sin(Π/2+α)),化简f(α)
已知f(α)=(sin(Π/2-α)cos(2Π-α)tan(-α+3Π))/(tan(Π+α)sin(Π/2+α)),化简f(α)
已知f(α)=(sin(Π/2-α)cos(2Π-α)tan(-α+3Π))/(tan(Π+α)sin(Π/2+α)),化简f(α)
f(α)=(sin(Π/2-α)cos(2Π-α)tan(-α+3Π))/(tan(Π+α)sin(Π/2+α))
=-cos(α)cos(α)tan(α)/(tan(α)cos(α))
=-cos(α)
答案:-cos(x)
求解过程:matlab代码实现
syms x;
f=(sin(pi/2-x)*cos(2*pi-x)*tan(-x+3*pi))/(tan(pi+x)*sin(pi/2+x));
g = simple(f)