若a(a-1)-(a^2-b)=-2,求2a^2-5ab+3b^2+2a的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 13:45:07
![若a(a-1)-(a^2-b)=-2,求2a^2-5ab+3b^2+2a的值](/uploads/image/z/1692178-34-8.jpg?t=%E8%8B%A5a%28a-1%29-%28a%5E2-b%29%3D-2%2C%E6%B1%822a%5E2-5ab%2B3b%5E2%2B2a%E7%9A%84%E5%80%BC)
若a(a-1)-(a^2-b)=-2,求2a^2-5ab+3b^2+2a的值
若a(a-1)-(a^2-b)=-2,求2a^2-5ab+3b^2+2a的值
若a(a-1)-(a^2-b)=-2,求2a^2-5ab+3b^2+2a的值
a(a-1)-(a^2-b)=-2
a^2-a-a^2+b=-2
-a+b=-2
a-b=2
2a^2-5ab+3b^2+2a
=2a^2-2ab-3ab+3b^2+2a
=2a(a-b)-3b(a-b)+2a
=2a*2-3b*2+2a
=4a-6b+2a
=6a-6b
=6(a-b)
=6*2
=12