2y+z分之x = 2x+y分之z=2z+x分之y=k,则k=
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![2y+z分之x = 2x+y分之z=2z+x分之y=k,则k=](/uploads/image/z/1652673-57-3.jpg?t=2y%2Bz%E5%88%86%E4%B9%8Bx+%3D+2x%2By%E5%88%86%E4%B9%8Bz%3D2z%2Bx%E5%88%86%E4%B9%8By%3Dk%2C%E5%88%99k%3D)
2y+z分之x = 2x+y分之z=2z+x分之y=k,则k=
2y+z分之x = 2x+y分之z=2z+x分之y=k,则k=
2y+z分之x = 2x+y分之z=2z+x分之y=k,则k=
x/(2y+z)=z/(2x+y)=y/(2z+x)=k
则
(2y+z)/x=(2x+y)/z=(2z+x)/y=1/k
根据何比定理
(2y+z)/x=(2x+y)/z=(2z+x)/y=(2y+z+2x+y+2z+x)/(x+y+z)=3
所以 1/k=3
k=1/3