2x²+1/2y²-2x-3y+5=0,求(2x√9x-y²√x/y³)-(√1/x-7x√y/x)的值
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2x²+1/2y²-2x-3y+5=0,求(2x√9x-y²√x/y³)-(√1/x-7x√y/x)的值
2x²+1/2y²-2x-3y+5=0,求(2x√9x-y²√x/y³)-(√1/x-7x√y/x)的值
2x²+1/2y²-2x-3y+5=0,求(2x√9x-y²√x/y³)-(√1/x-7x√y/x)的值
2x²+1/2y²-2x-3y+5=0
即
2(x-1/2)²+1/2 *(y-3)²=0
两个平方式相加为0,
那么两者都为0,
所以得到
x=1/2,y=3
于是
(2x√9x-y²√x/y³)-(√1/x-7x√y/x)
=3/√2 -√xy -√2+ 7√xy
=√2 /2+ 6√(3/2)
=0.5√2 +2√6