已知(5x+2y-12)²+|4x+7y-6|=0,则29x+29y=___
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![已知(5x+2y-12)²+|4x+7y-6|=0,则29x+29y=___](/uploads/image/z/1636998-6-8.jpg?t=%E5%B7%B2%E7%9F%A5%285x%2B2y-12%29%26%23178%3B%2B%7C4x%2B7y-6%7C%3D0%2C%E5%88%9929x%2B29y%3D___)
已知(5x+2y-12)²+|4x+7y-6|=0,则29x+29y=___
已知(5x+2y-12)²+|4x+7y-6|=0,则29x+29y=___
已知(5x+2y-12)²+|4x+7y-6|=0,则29x+29y=___
5x+2y-12=0
4x+7y-6=0
求出:x=-4y
y=2/3
所以:29x+29y=29*(-3y)=29*(-3)*2/3=-58