计算:[(2x+1)/(x²+x-2)]-[(x-2)/(x²-4)]如题
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计算:[(2x+1)/(x²+x-2)]-[(x-2)/(x²-4)]如题
计算:[(2x+1)/(x²+x-2)]-[(x-2)/(x²-4)]
如题
计算:[(2x+1)/(x²+x-2)]-[(x-2)/(x²-4)]如题
[(2x+1)/(x²+x-2)]-[(x-2)/(x²-4)]
=(2x+1)/[(x+2)(x-1)]-(x-2)/[(x+2)(x-2)]
=(2x+1)/[(x+2)(x-1)]-1/(x+2)
=(2x+1)/[(x+2)(x-1)]-(x-1)/[(x+2)(x-1)]
=[(2x+1)-(x-1)]/[(x+2)(x-1)]
=(x+2)/[(x+2)(x-1)]
=1/(x-1)
=(2x+1)/(x+2)(x-1)-(x-2)/(x+2)(x-2)
=(2x+1)/(x+2)(x-1)-1/(x+2)
=(2x+1-x+1)/(x+2)(x-1)
=(x+2)/(x+2)(x-1)
=1/(x-1)
您好:
[(2x+1)/(x²+x-2)]-[(x-2)/(x²-4)]
=(2x+1)/(x+2)(x-1)-(x-2)/(x+2)(x-2)
=(2x+1)/(x+2)(x-1)-1/(x+2)
=(2x+1-x+1)/(x+2)
=(x+2)/(x+2)
=1
如果本题有什么不明白可以追问,...
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您好:
[(2x+1)/(x²+x-2)]-[(x-2)/(x²-4)]
=(2x+1)/(x+2)(x-1)-(x-2)/(x+2)(x-2)
=(2x+1)/(x+2)(x-1)-1/(x+2)
=(2x+1-x+1)/(x+2)
=(x+2)/(x+2)
=1
如果本题有什么不明白可以追问,如果满意请点击“采纳为满意回答”
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