(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3,y=1/3
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(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3,y=1/3
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3,y=1/3
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3,y=1/3
答:
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)
=x^2-y^2+x^2-2xy+y^2-(3x^2-xy)
=2x^2-2xy-3x^2+xy
=-x^2-xy
=-x(x+y)
=-(-3)*(-3+1/3)
=-9+1
=-8
(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y
=x^2-y^2+x^2-2xy+y^2-3x^2+xy
=-x^2-xy
=-(-3)^2-(-2)(1/3)
=-9+2/3
=-25/3
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