看不清的和剩余的在这 8 :2^(x) 该方程实根为y=f(x)与y=a的交点,f(x)值域为【0,+∞】,a
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 15:50:42
![看不清的和剩余的在这 8 :2^(x) 该方程实根为y=f(x)与y=a的交点,f(x)值域为【0,+∞】,a](/uploads/image/z/15229288-64-8.jpg?t=%E7%9C%8B%E4%B8%8D%E6%B8%85%E7%9A%84%E5%92%8C%E5%89%A9%E4%BD%99%E7%9A%84%E5%9C%A8%E8%BF%99+8+%3A2%5E%28x%29+%E8%AF%A5%E6%96%B9%E7%A8%8B%E5%AE%9E%E6%A0%B9%E4%B8%BAy%3Df%28x%29%E4%B8%8Ey%3Da%E7%9A%84%E4%BA%A4%E7%82%B9%2Cf%28x%29%E5%80%BC%E5%9F%9F%E4%B8%BA%E3%80%900%2C%2B%E2%88%9E%E3%80%91%2Ca)
看不清的和剩余的在这 8 :2^(x) 该方程实根为y=f(x)与y=a的交点,f(x)值域为【0,+∞】,a
看不清的和剩余的在这 8 :2^(x)
该方程实根为y=f(x)与y=a的交点,f(x)值域为【0,+∞】,a
看不清的和剩余的在这 8 :2^(x) 该方程实根为y=f(x)与y=a的交点,f(x)值域为【0,+∞】,a
f(x)值域为【0,+∞),
y=f(x)与y=a有两个的交点,
当a>1时,y=f(x)与y=a只有一个的交点
所以 a∈(0,1)