配方法 解二元一次方程 1/2X²+2/5X-4/5=0 2X²+X=1 9(2X+3)²=4(2X-5)² (X-5){160-20(X-7)}=180(X-3)(X-1)=X-3 4X²-3X+1=0 a²X²+5aX-6=0 a(aX²+5X)=6
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![配方法 解二元一次方程 1/2X²+2/5X-4/5=0 2X²+X=1 9(2X+3)²=4(2X-5)² (X-5){160-20(X-7)}=180(X-3)(X-1)=X-3 4X²-3X+1=0 a²X²+5aX-6=0 a(aX²+5X)=6](/uploads/image/z/14936863-31-3.jpg?t=%E9%85%8D%E6%96%B9%E6%B3%95+%E8%A7%A3%E4%BA%8C%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B+1%2F2X%26%23178%3B%2B2%2F5X-4%2F5%3D0+2X%26%23178%3B%2BX%3D1+9%EF%BC%882X%2B3%EF%BC%89%26%23178%3B%3D4%EF%BC%882X-5%EF%BC%89%26%23178%3B+%EF%BC%88X-5%EF%BC%89%EF%BD%9B160-20%EF%BC%88X-7%EF%BC%89%EF%BD%9D%3D180%EF%BC%88X-3%EF%BC%89%EF%BC%88X-1%EF%BC%89%3DX-3+4X%26%23178%3B-3X%2B1%3D0+a%26%23178%3BX%26%23178%3B%2B5aX-6%3D0+a%EF%BC%88aX%26%23178%3B%2B5X%EF%BC%89%3D6)
配方法 解二元一次方程 1/2X²+2/5X-4/5=0 2X²+X=1 9(2X+3)²=4(2X-5)² (X-5){160-20(X-7)}=180(X-3)(X-1)=X-3 4X²-3X+1=0 a²X²+5aX-6=0 a(aX²+5X)=6
配方法 解二元一次方程
1/2X²+2/5X-4/5=0 2X²+X=1 9(2X+3)²=4(2X-5)² (X-5){160-20(X-7)}=180
(X-3)(X-1)=X-3 4X²-3X+1=0 a²X²+5aX-6=0 a(aX²+5X)=6
配方法 解二元一次方程 1/2X²+2/5X-4/5=0 2X²+X=1 9(2X+3)²=4(2X-5)² (X-5){160-20(X-7)}=180(X-3)(X-1)=X-3 4X²-3X+1=0 a²X²+5aX-6=0 a(aX²+5X)=6
先通过b^2-4ac判断其是否有值,b^2-4ac>=0则有实数解.然后通过x=-b/(2a)+(-)((b^2-4ac)/(4a))^0.5求解