先化简,在求值:[y(x-y)-x(x+y)]/(x²-y²)÷(x²+y²)/(x+y),其中x=2,y=-1
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![先化简,在求值:[y(x-y)-x(x+y)]/(x²-y²)÷(x²+y²)/(x+y),其中x=2,y=-1](/uploads/image/z/14398093-37-3.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%9C%A8%E6%B1%82%E5%80%BC%EF%BC%9A%5By%28x-y%29-x%28x%2By%29%5D%2F%EF%BC%88x%26%23178%3B-y%26%23178%3B%EF%BC%89%C3%B7%EF%BC%88x%26%23178%3B%2By%26%23178%3B%EF%BC%89%2F%EF%BC%88x%2By%EF%BC%89%2C%E5%85%B6%E4%B8%ADx%3D2%2Cy%3D-1)
先化简,在求值:[y(x-y)-x(x+y)]/(x²-y²)÷(x²+y²)/(x+y),其中x=2,y=-1
先化简,在求值:[y(x-y)-x(x+y)]/(x²-y²)÷(x²+y²)/(x+y),其中x=2,y=-1
先化简,在求值:[y(x-y)-x(x+y)]/(x²-y²)÷(x²+y²)/(x+y),其中x=2,y=-1
[y(x-y)-x(x+y)]/(x²-y²)÷(x²+y²)/(x+y)
=[-(x²+y²)]/(x²-y²)×(x+y)/(x²+y²)
=-(x+y)/(x²-y²)
=-1/(x-y)
=1/(y-x),
当x=2,y=-1时,原式=1/(-1-2)=-1/3.
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