解方程组:\left\{ \begin{array}{l}{\frac{x+3}{2}+\frac{y+5}{3}=7} \\ {\frac{x-4}{3}+\frac{2y-3}{5}
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![解方程组:\left\{ \begin{array}{l}{\frac{x+3}{2}+\frac{y+5}{3}=7} \\ {\frac{x-4}{3}+\frac{2y-3}{5}](/uploads/image/z/13954441-49-1.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%E7%BB%84%3A%5Cleft%5C%7B+%5Cbegin%7Barray%7D%7Bl%7D%7B%5Cfrac%7Bx%2B3%7D%7B2%7D%2B%5Cfrac%7By%2B5%7D%7B3%7D%3D7%7D+%5C%5C+%7B%5Cfrac%7Bx-4%7D%7B3%7D%2B%5Cfrac%7B2y-3%7D%7B5%7D)
解方程组:\left\{ \begin{array}{l}{\frac{x+3}{2}+\frac{y+5}{3}=7} \\ {\frac{x-4}{3}+\frac{2y-3}{5}
解方程组:\left\{ \begin{array}{l}{\frac{x+3}{2}+\frac{y+5}{3}=7} \\ {\frac{x-4}{3}+\frac{2y-3}{5}
解方程组:\left\{ \begin{array}{l}{\frac{x+3}{2}+\frac{y+5}{3}=7} \\ {\frac{x-4}{3}+\frac{2y-3}{5}
你的题目不完整呀
第一个方程是 (x+3)/2 + (y+5)/3 = 7
第二个是 (x-4)/3 + (2y-3)/5 =
请补充完整题目以便为你解答