设A={(x,y)|y=x-2},B={(x,y)|y/x-2=1},则CaB={?},讲解一下最好了,
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![设A={(x,y)|y=x-2},B={(x,y)|y/x-2=1},则CaB={?},讲解一下最好了,](/uploads/image/z/13938861-21-1.jpg?t=%E8%AE%BEA%3D%7B%28x%2Cy%29%7Cy%3Dx-2%7D%2CB%3D%7B%28x%2Cy%29%7Cy%2Fx-2%3D1%7D%2C%E5%88%99CaB%3D%7B%3F%7D%2C%E8%AE%B2%E8%A7%A3%E4%B8%80%E4%B8%8B%E6%9C%80%E5%A5%BD%E4%BA%86%2C)
设A={(x,y)|y=x-2},B={(x,y)|y/x-2=1},则CaB={?},讲解一下最好了,
设A={(x,y)|y=x-2},B={(x,y)|y/x-2=1},则CaB={?},讲解一下最好了,
设A={(x,y)|y=x-2},B={(x,y)|y/x-2=1},则CaB={?},讲解一下最好了,
A={(x,y)|y=x-2}
B={(x,y)|y/(x-2)=1}={(x,y)|y=x-2且x≠2}
A表示直线y=x-2上点的集合,B表示直线y=x-2上除点(2,0)个的其它点的集合
所以以A为全集,B的补集是:CaB={(2,0)}
自己画个图试试