分解因式:x²-y²-x+y=____________ a²-2ab+b²-1=__________
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![分解因式:x²-y²-x+y=____________ a²-2ab+b²-1=__________](/uploads/image/z/13875093-45-3.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%3Ax%26%23178%3B-y%26%23178%3B-x%2By%3D____________+a%26%23178%3B-2ab%2Bb%26%23178%3B-1%3D__________)
分解因式:x²-y²-x+y=____________ a²-2ab+b²-1=__________
分解因式:x²-y²-x+y=____________ a²-2ab+b²-1=__________
分解因式:x²-y²-x+y=____________ a²-2ab+b²-1=__________
解
x²-y²-x+y
=(x-y)(x+y)-(x-y)
=(x-y)(x+y-1)
a²-2ab+b²-1
=(a-b)²-1²
=(a-b+1)(a-b-1)
x²-y²-x+y=__(x-y)(x+y-1)_ a²-2ab+b²-1=___(a-b-1)(a-b+1)____
x²-y²-x+y
=(x²-y²)-(x-y)
=(x+y)(x-y)-(x-y)
=(x-y)(x+y-1)
a²-2ab+b²-1
=(a-b)²-1
=(a-b+1)(a-b-1)