已知x=1是方程x²-mx+1=0的根,化简根号下m²-6m+9,-根号下1-2m+m²
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![已知x=1是方程x²-mx+1=0的根,化简根号下m²-6m+9,-根号下1-2m+m²](/uploads/image/z/1267192-64-2.jpg?t=%E5%B7%B2%E7%9F%A5x%3D1%E6%98%AF%E6%96%B9%E7%A8%8Bx%26%23178%3B-mx%2B1%3D0%E7%9A%84%E6%A0%B9%2C%E5%8C%96%E7%AE%80%E6%A0%B9%E5%8F%B7%E4%B8%8Bm%26%23178%3B-6m%2B9%2C-%E6%A0%B9%E5%8F%B7%E4%B8%8B1-2m%2Bm%26%23178%3B)
已知x=1是方程x²-mx+1=0的根,化简根号下m²-6m+9,-根号下1-2m+m²
已知x=1是方程x²-mx+1=0的根,化简根号下m²-6m+9,-根号下1-2m+m²
已知x=1是方程x²-mx+1=0的根,化简根号下m²-6m+9,-根号下1-2m+m²
则1-m+1=0 得m=2
根号下m²-6m+9 =1
-根号下1-2m+m²=-1
0
1-m+1=0
所以m=2
根号下m^2-6m+9=根号下(m-3)^2=3-m=1
-根号下1-2m+m^2=-根号下(m-1)^2=-(m-1)=-1
由已知条件得 m=2 则根号下m平方减6m+9的结果为 1; -根号下1-2m+m的平方结果为-1