化简:√(12x²y+24x²y³),(X≥0,y≥0)
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![化简:√(12x²y+24x²y³),(X≥0,y≥0)](/uploads/image/z/12663170-26-0.jpg?t=%E5%8C%96%E7%AE%80%EF%BC%9A%E2%88%9A%EF%BC%8812x%26%23178%3By%2B24x%26%23178%3By%26%23179%3B%EF%BC%89%2C%EF%BC%88X%E2%89%A50%2Cy%E2%89%A50%EF%BC%89)
化简:√(12x²y+24x²y³),(X≥0,y≥0)
化简:√(12x²y+24x²y³),(X≥0,y≥0)
化简:√(12x²y+24x²y³),(X≥0,y≥0)
x≥0
所以|x|=x
原式=√[(4x²)(3y+6y³)]
=√[(2x)²(3y+6y³)]
=|2x|√(3y+6y³)
=2x√(3y+6y³)
√(12x²y+24x²y³)
=2x√(3y+6y³)