已知x+y=2,xy=7求x²y+xy²的值
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![已知x+y=2,xy=7求x²y+xy²的值](/uploads/image/z/1252800-0-0.jpg?t=%E5%B7%B2%E7%9F%A5x%2By%3D2%2Cxy%3D7%E6%B1%82x%26%23178%3By%2Bxy%26%23178%3B%E7%9A%84%E5%80%BC)
已知x+y=2,xy=7求x²y+xy²的值
已知x+y=2,xy=7求x²y+xy²的值
已知x+y=2,xy=7求x²y+xy²的值
x²y+xy²
=xy(x+y)
=2*7
=14
x²y+xy²=xy(x+y)=7*2=14
x²y+xy²
=xy(x+y)
=7×2
=14
解法如下:
x²y+xy²=xy(x+y)=7×2=14
(参考资料:习题答案)
它的值等于14